Dear CG,

Your help would be appreciated.

1-which system generates $30000/month, as indicated on the "home" page

2-how to have crosshairs stay active in Metatrader on all charts in a layout
without having to click every chart in the layout separately and on the
crosshairs tool

3- why doesn't the saved template, when applied, apply to all three new
open charts

Thank you.

Peter

I don't know whether you are searching this type of indicator.Any how I attached this indicator.

Attached Files

ADX Crossing.mq4 (2.2 KB, 21 views)

Hello codersguru,

Could you please build an EA for all interested persons here based on my simple system as follows.

I am testing this for quite some times and found really good results but due to time constraints I miss so many very good trades. Automation will definitely be helpful in this regard.

The rules.

Time Frame : 30 Min, 4 Major Pairs.

Entry : Camarilla Pivots H3 (buy) and L3 (sell) IF the JMA Slope is +ve and -ve respectively just at the times price touches H3/L3. Which means not at the close of bar but on real time.

Stop Loss : Initial SL well below pivot point just for safety but preferably the EA should close positions as per below mentioned rules.

Exit : 1) At H5 point for Buy and at L5 point for Sell trades.

2) JMA slope turns -ve (for Buy trades) at the end of the bar and vice versa.

Whichever between (1) and (2) occurs first.

Your help will be highly appreciated.

Thanks.

P.S : I have now posted this query on EA suggestion folder but can't delete this one. So if the moderator wants so you can delete this. Sorry for the trouble.

Attached Images

Camr+JMA.JPG (176.5 KB, 145 views)

Thanks alot Tirou,

You are the MAN

how do we merge two currencies pair onto the same chart?

__________________
Require your own unique EA? PM me.

CodersGuru,

I would like some help for coding an indicator that finds all inner bars in a chart and if finds one will show an arrow above such bar.
TimeFrame : M15 through H4

Inner Bar Definition : When the full length of a bar is less than that full length of the previous bar.
In other words, the highest and lowest of a bar don't exceed the higher and lowest of previous one. If highs and/or lows are equal it is NOT an inner bar.

Thanks,

Jos4x

Should this expression produce the same result?

if (High[i+1]>High[i+3] && High[i+1]>High[i+4])

if (High[i+1]>(High[i+3] && High[i+4]))

if (High[i+1]>(High[i+3] & High[i+4]))

They might and they might not: in words, the expressions would be something like the following:

The first expression says that "high of bar i+1 is greater than both high of bar i+3 and high of bar i+4".

The second expression says that "high of bar i+1 is greater than the truth value representation obtained from regarding both high of bar i+3 and high of bar i+4 as truth value representations"; here zero means false and non-zero means true, with a canoncial representation as 1.

The third expression says that "look at the bits of the highs of bar i+3 and bar i+4, and combine them with a bit-wise AND operation into whatever bit pattern that is, then reinterpret that bit pattern as a double number, and test whether high of bar i+1 is greater than that double number".

I'd love to see the EA/indicator

Nice 1!

So, when testing out whether the High[i+1] is > High[i+3] and also High[i+4] then:- if (High[i+1]>(High[i+3] && High[i+4])) ....

I'm attempting to modify existing code by adding 'perfection' setups to it here:- TD Sequential

Maybe you mean: if ( High[i+1] > MathMax( High[i+3], High[i+4] ) ) ...